n^2-n-6480=0

Solution for n^2-n-6480=0 equation:

n^2-n-6480=0

We add all the numbers together, and all the variables

n^2-1n-6480=0

a = 1; b = -1; c = -6480;
Δ = b2-4ac
Δ = -12-4·1·(-6480)
Δ = 25921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25921}=161$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-161}{2*1}=\frac{-160}{2}
=-80
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+161}{2*1}=\frac{162}{2}
=81
$